9sin^2(x)+6cos(x)=5

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Solution for 9sin^2(x)+6cos(x)=5 equation: 


Simplifying
9sin2(x) + 6cos(x) = 5

Multiply in2s * x
9in2sx + 6cos(x) = 5

Multiply cos * x
9in2sx + 6cosx = 5

Reorder the terms:
6cosx + 9in2sx = 5

Solving
6cosx + 9in2sx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9in2sx' to each side of the equation.
6cosx + 9in2sx + -9in2sx = 5 + -9in2sx

Combine like terms: 9in2sx + -9in2sx = 0
6cosx + 0 = 5 + -9in2sx
6cosx = 5 + -9in2sx

Divide each side by '6osx'.
c = 0.8333333333o-1s-1x-1 + -1.5in2o-1

Simplifying
c = 0.8333333333o-1s-1x-1 + -1.5in2o-1

Reorder the terms:
c = -1.5in2o-1 + 0.8333333333o-1s-1x-1

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